(1/2)^2x^2+3x-1=4^x-3

Solution for (1/2)^2x^2+3x-1=4^x-3 equation:

(1/2)^2x^2+3x-1=4^x-3

We move all terms to the left:

(1/2)^2x^2+3x-1-(4^x-3)=0


Domain of the equation: 2)^2x^2!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)^2x^2+3x-(4^x-3)-1=0

We add all the numbers together, and all the variables

3x+(+1/2)^2x^2-(4^x-3)-1=0

We get rid of parentheses

3x+(+1/2)^2x^2-4^x+3-1=0

We multiply all the terms by the denominator


3x*2)^2x^2+(-4^x*2)^2x^2+3*2)^2x^2-1*2)^2x^2+1=0

Wy multiply elements

6x^2-32x^4=0

We do not support expression: x^4